$16d^2-24d+6$

$\int_{\frac{\pi}{6}}^{\frac{\pi}{4}}\left(sinx\:+\:cosx\right)^2dx$

$2\left(x^2-4x\right)$

$-4\left(6\right)-6\left(-4\right)-\left(-2\right)$

$\int_0^1\left(-2x\right)dx$

$\frac{d}{dx}\left(\frac{\left(1+\sqrt{x}\right)^2\left(14+3y\right)^4}{\sqrt{11+y}}\right)$

$\left(-y+3\right)^3$