$\lim_{x\to1.99}\left(\frac{x^2-5x+6}{x-2}\right)$

$2x\left(\frac{\left(4x^2-3\right)}{3}\right)\left(1-x^2\right)^{\frac{2}{3}}$

$\int\left(\frac{2}{3}x^4\ln\left(x\right)\right)dx$

$\left(5x-3\right):\left(-2\right)>x+26$

$8\frac{1}{4}+3+3$

$\int x^2\left(x-4\right)^4dx$

$3x^2-7x-3=0$