$2\left(x^2-4x+6\right)-3x\left(x+7\right)$
$\frac{9x^3-2x^2+5x+4\:}{\left(x-3\right)}$
$\int\frac{xe^{5x^2}}{2}dx$
$\left(\tan x\right)\tan\left(2x\right)$
$\frac{3x^4}{12x^3}$
$\left(-5\right)+\left(-4\right)\cdot\left(+8\right)-\left(-15\right)$
$2x^2-6x=6x^2-8x$
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