$\frac{1}{a+6}+\frac{3}{a+4}=\frac{-2}{a^2+10a+24}$
$\left(4x^2y^5\right)^0$
$\left(x^2-9\right)\left(x+3\right)\left(x+3\right)$
$2mn\left(3p+4q\right)-5mp\left(3p+4q\right)+12p^2q+16pq^2$
$4x+12=2\left(x+12\right)$
$\frac{a^2}{ab}$
$v=5t-\frac{1}{2}t^2$
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