$x''-7x'+12x=0$
$\int_0^{\infty}\left(7e^{-7x}\right)dx$
$-3\left(2\right)\left(3\right)-9+5$
$\left(3x-7\right)\cdot\left(3x+7\right)$
$y=-\frac{1}{2}\left(2^x\right)$
$\left(1+tan\left(x\right)\right)\cdot\frac{sin\left(x\right)}{sin\left(x\right)+cos\left(x\right)}=\tan\left(x\right)$
$\left(2x+y\right)^2\left(mn+2\right)^2\left(7x^3y+4\right)^2$
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