$x^2+18x+17$
$2\sqrt{32}+\sqrt{8}$
$\lim_{x\to\infty}\left(\frac{\left(x+1\right)\left(x+2\right)}{\left(x+3\right)\left(x+4\right)}\right)$
$4\left(-7-8x\right)-3x$
$\sqrt{x^3-1-\frac{2}{x}}$
$-x^3-2x^2+5x+6$
$\left(x+2\right)\left(x+3\right)+3\left(x+2\right)\le0$
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