$\lim_{x\to\infty}\left(\frac{e^{x+1}}{\left(\frac{5}{2}\right)^x}\right)$
$16x^6-32x^5-48x$
$\lim_{x\to2}\left(x-24\right)$
$7x+12=10x$
$16x^2-12x+9$
$4\left(2x^2+x\right)+4\left(3x+2\right)$
$-100\::-10$
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