$5=v+15$

$\left|12-15\right|+\left|-4-3\right|$

$\int\frac{4x-5}{2x^3-5x^2-3x}dx$

$\left(-5x^3y^7\right)^3$

$\left(2\sqrt{a}+\sqrt{b}\right)^2\left(2\sqrt{a}-\sqrt{b}\right)^2$

$\lim_{x\to1}\left(\frac{x^{2}-5x+4}{x-1}\right)$

$\lim_{x\to\infty}\left(\frac{16x^2-3x+6}{8x^2+6x+8}\right)$