$\left(\sin\left(x\right)-\:\cos\left(x\right)\right)^2=1\:-\:\sin\left(2t\right)$
$\left(-x^2\right)\left(2x^3+3\right)$
$3x^3-9x^2$
$x-5x+36$
$7\int\left(cos\left(4x\right)\right)^3dx$
$7^2-51x-40$
$x'=\left(3+x\right)\left(5+t\right)$
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