$\frac{9-y^2}{\sqrt[3]{y^2+9+\sqrt[3]{6y}}}$
$\:1.x^2+3x-18=\:\:$
$100=d+70m^2+4d-3m^2-y^2+25m^2$
$5x\:+\:7x\:+\:9x\:+4x$
$\left(-8\right)+\left(10\right)\left(-8\right)+\left(10\right)$
$y^2-15y+54$
$\int x\sqrt[3]{2x+3}dx$
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