$\sqrt{\frac{\sqrt{3^x}}{3^x\sqrt{\left(3^x\right)}^3}}$
$\lim_{x\to0}\left(\frac{\sqrt{15}\cdot\sin\left(x\right)-x}{15\cdot x^3}\right)$
$\left(4x+15\right)^2$
$657\:+\:-295\:$
$\lim_{x\to\infty}\:3x-\sqrt{x^2+x-1}$
$7x-8\left(x-2\right)\ge0$
$5.1^2$
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