$5 y + 2 > 3 y - 8$
$\frac{s^2}{s^4-1}$
$6y''+y'-y=0$
$\int_x^4dx$
$\lim_{x\to0}\left(\frac{2-2\sin\left(x\right)}{1+\cos\left(2x\right)}\right)$
$3x\:+\:x\:+\:6\:+\:10\:$
$5b-14=8b+4$
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