$6\:+\:l\:=\:l\:+\:6$
$\left(4-8x\right)^{-\frac{1}{2}}$
$-5xy+4xy$
$4-0.75$
$120\cdot120$
$32m^2-8n^4$
$\lim_{x\to\infty}\left(\frac{\left(1+4x^2\right)}{x^2}\:\:\right)$
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