$\sqrt[6]{25^3}$
$\int12\cdot\:\left(\frac{1}{12}+\frac{1}{3}x+\frac{1}{4}x^2\right)in\left(x\left(1+x\right)^2\right)dx$
$2x^2-6x+3<0$
$\left(\frac{2}{3}x^3-\frac{1}{2}y\right)^2$
$\left(x^{-2}\right)^{-3}$
$\left(12x^2-24x+24\right)e^x$
$\frac{4^{-3}}{4^{-7}}$
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