$\frac{81}{100}a^2b-\frac{16}{49}b^2a$
$-\frac{6}{x}-\frac{2}{9}=\frac{2}{x}$
$\frac{5}{8}x^2-x^2+\frac{x^3}{3}$
$\left(-u+x\right)^3$
$4m+12m-6$
$x^2=77$
$\left(8\right)-\left(-7\right)$
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