$\lim_{x\to2}\left|x\right|$
$t^2-4t+4$
$y'+x=0$
$2cos3x-1=0$
$\frac{16x^4\:-\:39.0625}{2x\:+\:2.5}$
$\int\:\frac{x^4+3x+21}{\sqrt{x}}dx$
$\lim_{x\to\infty}\left(\frac{2x^3-2x-8}{2x^2-7x-6}\right)$
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