$\frac{1}{9}x^2+\frac{2}{3}xy+y^2$
$-9-\left(2-9\right)$
$5x^2+14x+4=0$
$3-7\cdot\left(-2\right)\cdot4$
$2\left(b-5\right)+14=5b-3\left(b+8\right)$
$\left(x-4\right)\left(x+8\right)$
$7x^2-16x-4$
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