$4x^4-9y^2z^2$
$\frac{dy}{dx}=\frac{x}{-3x-2y}$
$\left(3x^2\right)\left(-2x^4\right)$
$\frac{2x^3-2x^2-2x+3}{x-1}$
$\:\left(-5+a\right)^2$
$\frac{\left(\frac{x+6}{3}\right)}{\left(\frac{x}{7}\right)}$
$\left(xy^2-x\right)dx+\left(y-x^2y\right)dy=0$
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