$\int\left(\frac{\left(2x\right)}{\left(4+3x^2\right)^2}\right)dx$
$3x^2+12x+15$
$x^2-6x=6$
$8x-30=2x-6$
$2x^2+x-400=0$
$=3x^2-5x+4$
$x^2+x+2x-5+3x^2+7$
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