$3x^2+12x+12$
$3xy\cdot15xy$
$\left(3x+\frac{1}{3}\right)^2$
$\left(b+3\right)\left(b+8\right)$
$\sqrt{-6}-6$
$6a\cdot6a$
$\left(-7\right)\left(-8\right)-\left(12\right)\left(-7\right)$
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