$\int\frac{z^3}{\sqrt{4+z^2}}dz$
$w+5x-168=0$
$\left(-125\right)\cdot27$
$-\left(3x+9\right)^2$
$\int x^{20}dx$
$\left(\frac{2}{3}x-\frac{1}{2}\right)\left(\frac{2}{3}x+\frac{5}{3}\right)$
$\lim_{x\to\infty}\left(1+2x\right)^{\left(3cot\:x\right)}$
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