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Find the limit of $3x+1$ as $x$ approaches 0

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e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Limits by direct substitution | Limits and continuity | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=cfOcOgr0E7U

_-substitution: definite integral of exponential function | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=1ct7LUx23io

Undefined limits by direct substitution | Limits and continuity | AP Calculus AB | Khan Academy

https://www.youtube.com/watch?v=JlOyb_RTejo

Calculus - Evaluating a limit by rationalizing the radical, lim(x tends to 0) (sqrt(x + 1) - 1)/x

https://www.youtube.com/watch?v=v8dIvXm03dw

Limit of (sin x)/x as x approaches 0

https://www.youtube.com/watch?v=5xitzTutKqM

Solve for the Zeros Using Quadratic Formula

https://www.youtube.com/watch?v=tv7b5l5UT4Q
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1
2
3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

Tips on how to improve your answer:

$\lim_{x\to0}\left(3x+1\right)$

Time to solve it:

~ 0.03 s