$\frac{x^3-4x-10}{x^2-x+6}$
$x+26=-4$
$\left(3y^3+5-6y\right)\left(y^2+2\right)$
$6-4:2-5.3+6:2.2$
$\frac{\left(12-5x\right)}{6-5x-x^2}$
$\left(\sqrt[3]{x}-h\right)^2$
$\lim_{x\to0\:y\:\to\:0}\frac{3xy}{4x^2+5y^2}$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!