$12x^2+3x=0$

$\int\frac{4}{\left(t+13\right)^2}dt$

$\left(1+cot\left(\theta\right)\right)\left(1-cot\left(\theta\right)\right)-csc^2\left(\theta\right)$

$\frac{3xy^9}{2y^{-2}}.\frac{-7y}{42x^5}$

$m+4=-12$

$\left(4x^4y\right)\left(-2xy^2\right)\left(3x^6y\right)\left(-2y^4\right)$

$81=5-8cos\:\theta$