$5x^2-3x+x-5$
$\lim_{x\to0}\left(\frac{5\cdot sin\left(4x^8\right)}{-4x}\right)$
$\left(4ab^4\right)\left(-7ab^3\right)$
$f\left(x\right)=\left(x^2+3x\right)\left(4x^3-6x\right)$
$m^2+6m=7$
$.254-.05$
$36x^2+60xy+25y^2-9x^2+12xy-4y^2$
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