$\lim_{x\to\infty}\left(3^x-\sqrt{9^x-3^x+4}\right)$
$81a^{36}-64b^{16}$
$-24xy^2\:+\:5x^3\:-\:15\:-3xy^2\:+\:2x\:-\:11x^3\:+6$
$\left(\frac{a}{2}\right)^2-\left(\frac{b}{4}\right)^2$
$12x-13=-x^2$
$\lim_{h\to0}\left(\frac{\left(4+h\right)^2-16}{5}\right)$
$6-\left(-7\right)-\left(-3\right)-16$
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