$3-\left(4-7-2\right)+\left(-5+8-1\right)$
$\frac{2x^3+3x-10}{x+3}$
$x^2+16x+40$
$\left(4a+10\right)\left(4a-10\right)$
$\left(x^8y^2+4x^5y\right)$
$\left(-980\right)-\left(+360\right)$
$0.01+00.02+0.02+000.55+00.40+10.60+0.50$
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