$2x-3x^2+\frac{3}{2}=x+\frac{1}{2}x^2$
$\frac{396}{22}$
$\frac{tan}{csc}$
$\int\frac{1+\sqrt{y}}{y^2}dx$
$28m^4+40m^2+16$
$2-3+2-7$
$-\left(-5+7-3\right)-\left(7-2\right)\cdot\left(-2\right):\left(-4+2\cdot\left(-4+6\right)-2\right)$
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