$\frac{d^3}{dx^3}\sqrt[3]{6x+1}$
$r^2+16r+64$
$\frac{d^2}{dx^2}\tan\left(x\right)$
$2b\:+\:9c\:+\:4b\:-\:6c$
$27x^2+18x+9$
$x^2+9x+220$
$-6xy+25y^2$
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