$\frac{x}{6}<7$
$25^4-40x^2+16$
$-7x\left(-9x^2+4\right)$
$5x-3x-9x$
$\left(-5\right)-\left(8\right)-\left(-10\right)-\left(3\right)$
$\left(\frac{x\left(x^3-x^2+x+1\right)}{\left(x+1\right)\cdot\left(x-1\right)}\right)$
$25\cdot\left(18\right)\cdot\left(-16\right)\cdot\left(-1\right)$
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