$12+4-16+48-3$
$\int\frac{1}{\sqrt{9\:-\:16x\:-\:4x^2}}dx$
$8\:sec\:y\:cos\:y\:$
$\frac{x^4+4x^3-4x^2+5}{x-2}$
$25x^2+40xy+16y^2$
$\left(3x^5y^2+\frac{2}{3}y\right)\left(3x^5y^2-\frac{2}{3}y\right)$
$\frac{x^7-6x^4-8x^2y}{x-2}$
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