$\lim_{x\to0}\left(\frac{\left(2\right)^x}{x^2+1}\right)$
$\left(l\:+\:5\right)\left(l\:-\:5\right)$
$2x+7\le x+12$
$3am-6bm+5an-10bn$
$\frac{5}{3}xz-\frac{6}{2}xy^2z-\frac{6}{3}xz$
$\frac{d^2y}{dx^2}\cdot y^2-k=0$
$\frac{8x^5+4x^3+19x^2+10x+16}{2x^3+x^2+3}$
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