$\int\frac{2x-5}{3x^2-5}dx$
$3x^2-3x+6-x+3$
$6-\left(-27\right)$
$\:\:2\:\cdot5^4\:+\:5-\:1\:$
$2\cdot2\sqrt{2}$
$9-4.5+6-7$
$-\left(+8\right)-\left(-6+6-2\right)$
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