$\int\frac{\left(4x+13\right)}{x^2+3x-10}dx$

$\frac{dy}{dx}=\frac{2xy}{x^2+1}+x^3$

$-32\cdot\left(-27\right)$

$\int\left(12sin^7\left(3x\right)cos^8\left(3x\right)\right)dx$

$10\:\cdot10\:\cdot10\:\cdot10^{-3}$

$2\frac{dy}{dx}+5x=6$

$sin\left(x\right)=cos\left(\frac{\pi}{2}-x\right)$