$\frac{8\left(-\sqrt{3}\sqrt{x}+24\right)}{3},\:x=27$
$y^2x^{-4}$
$\left(2x^{n+1}+\frac{3}{7}y^n\right)^4$
$-3\sqrt{2}+5\sqrt{2}$
$\frac{9}{16\:}^{-2}$
$2\pi+7-\sqrt[8]{2}+5\pi-\sqrt[3]{2}$
$y^{'\:}-3y=6$
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