$\frac{12g^2}{25}.\:\frac{40}{9g^4}$
$y''+20y'+100y=0$
$\frac{dy}{dx}=-67y+12$
$6^2:\:4+3\cdot9-3$
$\lim_{x\to0}\left(\frac{x^2+3x}{x}\right)$
$2x+6^2$
$( 5 b ^ { 2 } - 2 c ) ^ { 3 }$
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