$12a^2bc^3-5a^2bc^3+3a^2bc^3-2a^2bc^3$
$\frac{\sin^2t\left(\sec t+\cos\sec t\right)}{\cos t\tan t}=1+\tan t$
$\left(3x^{4a-5}\right)^2$
$9y-10x-4+8x$
$\left(12y-15a\right)^2$
$-x^2+x-48=0$
$\sqrt{x+3}-5=6$
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