$t\cdot\frac{dy}{dx}=x+1$
$\left(-7\right)\left(4\right)\left(-9\right)\left(10\right)$
$-4\:\cdot8$
$\sqrt[4]{x^8}y^{12}$
$\frac{2x^4-6x^3+x-10}{x^2}$
$\left(senx\:+\:cos\:x\right)^4$
$\frac{27x^3+8}{x^2-16x+28}$
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