$3a^2+3^2$
$\frac{z+10}{z^2\left(z-1\right)}$
$\left(3-\frac{1}{4}x^2\right)^2$
$2x^2-11x+12$
$\frac{\left(_{1-\left(cos^2\left(x\right)\right)}\right)}{tan^2\left(x\right)}+2sin^2\left(x\right)$
$-3x<-11$
$2x-14=4x+6$
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