$\frac{\left(a+b\right)^3-\left(a-b\right)^3}{3ab^2+b^2}$
$4xy\frac{dx}{dy}=x+1$
$x\:+\:3\:=\:-23$
$\sqrt[5]{a^7b^4c^{12}}$
$\left(a+6\right)\left(a+2\right)-\left(a+4\right)^2$
$10v^2-23+12$
$11x^2+66x=0$
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