$2x^2-25x+72$
$3\left(-8\right)^4-3\left(-8\right)^3-\left(-8\right)^2+3\left(-8\right)-1\:$
$5x^2-3\cdot5x^2+3x$
$\left(2x\:^3\:+y\right)\:^2$
$y^{'''}+16y'=0$
$0=x^2-8x+10$
$2.1-3$
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