$\left(8x\:+\:yz\right)^2$
$\left(7x\right)\left(5x\right)^4$
$\left(\left(4x\right)-\left(3y\right)-\left(2z\right)\right)^2$
$2x-4<x+3$
$\frac{2}{x}=\frac{x}{5x+1}$
$xy\frac{dy}{dx}=\frac{1}{\left(x+1\right)}$
$\left(1+\frac{\tan\:\left(x\right)}{\cot\:\left(x\right)}\right)\left(\cos\left(x\right)^2\right)=1$
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