$3a+4=40$
$\sqrt[5]{x^2}=9$
$\left(5x+10\right)\left(5x+14\right)$
$\frac{x-\frac{x^3}{6}}{1+x}$
$4x-8=0$
$\int\left(1-\cos\left(2x\right)\right)^3\cdot\sin\left(2x\right)dx$
$\left(\frac{1}{6}^{-3}=\left(x+7\right)\right)$
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