$5x^3y^2z-2y^4z^6$
$14-6xs+14xs+8$
$\left(\frac{1}{3}x\:+\frac{1}{2}y\right)^2$
$s^2-6s+9=0$
$x''+16x=0$
$\frac{3}{x^2-25}=\frac{5}{x-5}-\frac{x}{x+5}$
$2x^2-14x+9$
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