$\lim_{x\to-1}\left(\frac{x^2+4x+3}{x^3-1}\right)$
$4t^2-3t+9=0$
$\int x\left(6x^2+8\right)^7dx$
$\left(4k^4-z^3\right)^2$
$\left(2\right)^{8x}=\left(32\right)^8$
$\frac{dy}{dx}-y=3$
$5x^2+10x-5$
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