$\tan^240$
$250x^2-40$
$-156x-73x+18x$
$\left(\left(\left(-3\right)^3\right)^2\right)^4$
$\left(x^2\:+\:1\right)\frac{dy}{dx}=\:sec\:y$
$-x^2-4x-5$
$\int3e^{3x}dx$
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