$x^3+3x^2-5-6$
$\left(-5x\right)+12+7x$
$6\left(2^3+5\right)-\left(3-1\right)^2$
$y'-4y=0.8$
$-3\left(x-7\right)$
$\sqrt{64-15-2\cdot3^2}$
$5.0\cdot10^2\cdot6.0\cdot10^5$
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