$6-\left(-32\right)$
$\frac{dy}{dx}=\frac{\left(y^2\left(x-3\right)\right)}{x^3}$
$\log_x\left(y\right)-3=\log_x\left(\frac{5}{x}\right)$
$\left(-xy^{\frac{1}{3}}\right)^9$
$\left(x-1\right)\left(x-3\right)\left(x-5\right)$
$6x-mx=2+m$
$-10-8+6-4-3+2$
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