$\left(-4\right)^2+6\left(-4\right)+24$
$x^2+1x-600$
$3+4+8$
$\left(6x^3-3y\right)^2$
$m^{2-\left(8\right)}$
$-0.07\left(7.5\right)^2+0.73\left(7.5\right)+0.18$
$\int\frac{8x+1}{\left(x-2\right)\left(x+3\right)}dx$
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