$6n^2m^2\left(-n^3m^2-3\right)$
$-5\cdot2+\left(6\right)\left(-5\right)\left(2\right)-\left(-3\right)\left(5\right)-\left(-4\right)\left(-2\right)-7$
$6\frac{1}{6}$
$x^2-14+144$
$\frac{10}{2}+7.\left(-3\right)$
$6x^2+x-2=0$
$\sqrt{9-x}=2$
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